E and F are points on the sides AB and AC respectively of a △ ABC such that AE/EB = AF/FC = 1/2 . Which of the…

CBSE Class 10 Maths PYQ · Triangles · Similarity of Shapes · 1 Mark · March 2025 · Standard

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41 Mark · March 2025 · Standard

E and F are points on the sides AB and AC respectively of a $\triangle ABC$ such that $\frac{AE}{EB} = \frac{AF}{FC} = \frac{1}{2}$. Which of the following relation is true ?

(a)$EF = 2BC$
(b)$BC=2EF$
(c)$EF = 3BC$
(d)$BC = 3 EF$

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(d) $BC = 3 EF$

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E and F are points on the sides AB and AC respectively of a △ ABC such that AE/EB = AF/FC = 1/2 . Which of the…

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